Answer
$$ y ^{\prime}=\frac{1}{\ln 10}$$
Work Step by Step
Given $$ y =\log _{10} e^x $$
Since $$\log_{a}z=\frac{\ln z}{\ln a}$$ So, we have
\begin{aligned}
y& =\log _{10} e^x\\
&=\frac{\ln e^x}{\ln 10}\\
&=\frac{x\ln e}{\ln 10} \\
&=\frac{x }{\ln 10}\\
&\Rightarrow y^{\prime}=\frac{1}{\ln 10}
\end{aligned}