Answer
$\frac 1 {12}(6x+sin6x)+C$
Work Step by Step
$\int cos^23xdx$
$\int \frac {1+cos6x} 2dx$
$\frac 1 2(x+\frac 1 6 sin6x)+C$
$\frac 1 {12}(6x+sin6x)+C$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 8 - Integration Techniques, L'Hopital's Rule, and Improper Integrals - 8.3 Exercises - Page 530: 9
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