Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 7: Transcendental Functions - Practice Exercises - Page 439: 11

Answer

$$\frac{{dy}}{{dx}} = 18{x^{2.6}}$$

Work Step by Step

$$\eqalign{ & y = 5{x^{3.6}} \cr & {\text{Find the derivative of }}y{\text{ with respect to }}x \cr & \frac{{dy}}{{dx}} = \frac{d}{{dx}}\left[ {5{x^{3.6}}} \right] \cr & \frac{{dy}}{{dx}} = 5\frac{d}{{dx}}\left[ {{x^{3.6}}} \right] \cr & {\text{use the power rule: }}\frac{d}{{dx}}\left[ {{x^n}} \right] = n{x^{n - 1}} \cr & \frac{{dy}}{{dx}} = 5\left( {3.6{x^{3.6 - 1}}} \right) \cr & \frac{{dy}}{{dx}} = 18{x^{2.6}} \cr} $$
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