Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 7: Transcendental Functions - Practice Exercises - Page 439: 1

Answer

$$-2e^{-x/5}$$

Work Step by Step

Given $$ y=10 e^{-x / 5} $$ Then \begin{align*} y'&= 10e^{-x/5} \frac{d}{dx}(-x/5)\\ &=-2e^{-x/5} \end{align*}
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