Calculus: Early Transcendentals 9th Edition

Published by Cengage Learning
ISBN 10: 1337613924
ISBN 13: 978-1-33761-392-7

Chapter 3 - Section 3.6 - Derivatives of Logarithmic Functions - 3.6 Exercises - Page 224: 11

Answer

$F'(t)=(\ln t)^2cos(t)+\frac{2\ln t\times sin(t)}{t}$

Work Step by Step

$F(x)=(\ln t)^2sin(t)\\ F'(x)=(\ln t)^2cos(t)+\frac{2\ln t}{t}\times sin(t)\\ F'(t)=(\ln t)^2cos(t)+\frac{2\ln t\times sin(t)}{t}$
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