Answer
=$ e^{sin^{2}θ}$ + c
Work Step by Step
Equation = $\int sin2θ e^{sin^{2}θ} dθ $
Let u = ${sin^{2}θ}$
u = $\frac{1}{2} . (1-cos2θ)$
du = $\frac{1}{2} . -(-2sin2θ) dθ $
du = $(sin2θ )dθ$
Putting values in equation
=$\int e^{u} du$
= $e^{u}$ + c
Putting value of "u"
=$ e^{sin^{2}θ}$ + c
