Answer
$\frac{2}{5}$ $\sqrt (5s+4)$ + C
Work Step by Step
$u$ = $5s+4$
$du$ = $5ds$
$\int$ $\frac{1}{\sqrt (5s+4}$ $ds$ = $\frac{1}{5}$$\int$ $\frac{1}{\sqrt u}$ $du$
= $\frac{2}{5}$ $\sqrt u$ + C
= $\frac{2}{5}$ $\sqrt (5s+4)$ + C
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 5: Integrals - Section 5.5 - Indefinite Integrals and the Substitution Method - Exercises 5.5 - Page 295: 18
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