Answer
$\frac{2}{3}sin^{3/2}x-\frac{2}{7}sin^{7/2}x+C$
Work Step by Step
Let u=$sin x=>du=cosxdx$
=$\int \sqrt{sinx}(1-sin^2x)cosxdx$
=$\int (u^{1/2}-u^{5/2})du$
=$\frac{2}{3}u^{3/2}-\frac{2}{7}u^{7/2}+C$
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