Answer
= $\frac{1}{2cos(2t+1)}$ + c
Work Step by Step
$u$ = $cos (2t+1)$
$du$ = -$2sin(2t+1)$ $dt$
$\int$$\frac{sin(2t+1)}{cos^{2}(2t+1)}$ $du$ = -$\frac{1}{2}$$\int$ $\frac{1}{u^{2}}$ $du$
= $\frac{1}{2u}$ + c
= $\frac{1}{2cos(2t+1)}$ + c
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 5: Integrals - Section 5.5 - Indefinite Integrals and the Substitution Method - Exercises 5.5 - Page 295: 31
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