Answer
= $2(sec z)^{\frac{1}{2}}$ + $c$
Work Step by Step
$sec$ $z$ = $u$
$sec$ $z$ $tan$ $z$ $dz$ = $du$
$\int$ $\frac{secztanz}{\sqrt sec z}$ $dz$ = $\int$ $\frac{1}{\sqrt u}$ $du$
= $2u^{\frac{1}{2}}$ + $c$
= $2(sec z)^{\frac{1}{2}}$ + $c$
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 5: Integrals - Section 5.5 - Indefinite Integrals and the Substitution Method - Exercises 5.5 - Page 295: 32
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