Chapter 5: Integrals - Section 5.5 - Indefinite Integrals and the Substitution Method - Exercises 5.5 - Page 295: 17

-$\frac{1}{3}$ $(3-2s)^{\frac{3}{2}}$ + C

$u$ = $3-2s$ $du$ = $-2ds$ $\int$ $\sqrt(3-2s)$ $ds$ = -$\frac{1}{2}$$\int$ $\sqrt u^{\frac{1}{2}}$ $du$ = -$\frac{1}{3}$ $u^{\frac{3}{2}}$ + C = -$\frac{1}{3}$ $(3-2s)^{\frac{3}{2}}$ + C