Answer
$$\sin (\sin t)+C $$
Work Step by Step
Given $$ \int \cos t \cos (\sin t) d t $$
Let
$$u=\sin t \ \ \ \ \Rightarrow \ \ \ du =\cos tdt$$
\begin{aligned} \int \cos t \cos (\sin t) d t &=\int \cos u d u \\ &=\sin u+C \\
&=\sin (\sin t)+C \end{aligned}