Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 3: Derivatives - Section 3.6 - The Chain Rule - Exercises 3.6 - Page 149: 78

Answer

a. $\frac{3\sqrt x}{2}$, b. $\frac{3\sqrt x}{2}$

Work Step by Step

a. $\frac{dy}{dx}=\frac{dy}{du} \frac{du}{dx}=(3u^2)(\frac{1}{2\sqrt x})=(3x)(\frac{1}{2\sqrt x})=\frac{3\sqrt x}{2}$ b. $\frac{dy}{dx}=\frac{dy}{du} \frac{du}{dx}=(\frac{1}{2\sqrt u})(3x^2)=(\frac{1}{2x\sqrt x})(3x^2)=\frac{3\sqrt x}{2}$
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