Answer
$2$
Work Step by Step
$r$ = $sin(f(t))$
$\frac{dr}{dt}$ = $\frac{d}{dt}$[$sin(f(t))$] = $cos(f(t))$[$f'(t)$]
$\frac{dr}{dt}$ = $r'(0)$ = $cos(f(0))$[$f'(0)$] = $cos(\frac{\pi}{3})$[$4$]= $(\frac{1}{2})$$(4)$ = $2$
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 3: Derivatives - Section 3.6 - The Chain Rule - Exercises 3.6 - Page 149: 72
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