Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 3: Derivatives - Section 3.6 - The Chain Rule - Exercises 3.6 - Page 149: 71

Answer

$3(1+\frac{1}{x}) ^2 \cdot \frac{1)}{x^3}$.

Work Step by Step

To find the second derivative of the given function $y = (1 + \frac{1}{x})^3$, we can use the chain rule and the power rule for differentiation. The chain rule states that the derivative of a composite function is the derivative of the outer function times the derivative of the inner function. The power rule states that the derivative of $x^n$ is $n \cdot x^{n-1}$. Applying the chain rule, we differentiate the outer function $u^3$ with respect to $u$ to get $3u^2$. Applying rule, we differentiate the inner function $1 + \frac{1}{x}$ with respect to $x$ to get $\frac{-1}{x^2}$. Therefore, the first derivative of the given function is $3(1 + \frac{1}{x})^2 \cdot \frac{-1}{x^3}$.
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