Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 3 - Applications of Differentiation - Review Exercises - Page 238: 19

Answer

The theorem can not be applied because f is not continuous on the closed interval $[-2,1]$.

Work Step by Step

The Mean Value Theorem If $f$ is continuous on the closed interval $[a, b]$ and differentiable on the open interval $(a, b)$ , then there exists a number $c$ in $(a, b)$ such that $f^{\prime}(c)=\displaystyle \frac{f(b)-f(a)}{b-a}.$ ---- f is not defined for $x=0\in[-2,1] ,$ so it is not continuous on the closed interval $[-2,1]$. A premise of the theorem is not satisfied, so the theorem can not be applied.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.