Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 9 - Solving Quadratic Equations - 9.1 - Properties of Radicals - Exercises - Page 487: 97

Answer

$9\sqrt 3-\sqrt[5] {9}$

Work Step by Step

$6\sqrt[4] {9}-\sqrt[5] {9}+3\sqrt[4] {9}=6\sqrt[4] {9}+3\sqrt[4] {9}-\sqrt[5] {9}$ $=(6+3)\sqrt[4] {9}-\sqrt[5] 9$ $=9\sqrt[4] {9}-\sqrt[5] {9}$ $=9\sqrt[4] {3^2}-\sqrt[5] {9}$ $=9\sqrt{3}-\sqrt[5] {9}$
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