Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 9 - Solving Quadratic Equations - 9.1 - Properties of Radicals - Exercises - Page 487: 77

Answer

$-13\sqrt{6}$

Work Step by Step

The given expression is $=2\sqrt{6}-5\sqrt{54}$ Factor as square terms. $=2\sqrt{6}-5\sqrt{9\cdot 6}$ Use product property of square roots. $=2\sqrt{6}-5\sqrt{9}\cdot \sqrt{6}$ Use $9=3^2$. $=2\sqrt{6}-5\sqrt{3^2}\cdot \sqrt{6}$ Simplify. $=2\sqrt{6}-5\cdot 3\sqrt{6}$ $=2\sqrt{6}-15\sqrt{6}$ Use distributive property. $=(2-15)\sqrt{6}$ Subtract. $=-13\sqrt{6}$
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