Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 9 - Solving Quadratic Equations - 9.1 - Properties of Radicals - Exercises - Page 487: 71

Answer

$=-6\sqrt{2}$ $\approx -8.49$

Work Step by Step

The given function is $=-\sqrt{2a^2+b^2}$ Substitute $-2$ for $a$ and $8$ for $b$. $=-\sqrt{2(-2)^2+(8)^2}$ Simplify. $=-\sqrt{8+64}$ $=-\sqrt{72}$ Factor as square term. $=-\sqrt{36\cdot 2}$ $=-\sqrt{6^2\cdot 2}$ Use product property of square roots. $=-\sqrt{6^2}\cdot \sqrt{2}$ Simplify. $=-6\sqrt{2}$ Rounded to the nearest hundredth. $\approx -8.49$
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