Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 9 - Solving Quadratic Equations - 9.1 - Properties of Radicals - Exercises - Page 487: 80

Answer

$7\sqrt{7}-5\sqrt{14}$

Work Step by Step

The given expression is $=3\sqrt{7}-5\sqrt{14}+2\sqrt{28}$ Factor as square terms. $=3\sqrt{7}-5\sqrt{14}+2\sqrt{4\cdot 7}$ Use product property of square roots. $=3\sqrt{7}-5\sqrt{14}+2\sqrt{4}\cdot \sqrt{7}$ Use $\sqrt {4}=2$. $=3\sqrt{7}-5\sqrt{14}+2\cdot 2\sqrt{7}$ $=3\sqrt{7}-5\sqrt{14}+4\sqrt{7}$ Use commutative property of addition. $=3\sqrt{7}+4\sqrt{7}-5\sqrt{14}$ Use distributive property. $=(3+4)\sqrt{7}-5\sqrt{14}$ Add. $=7\sqrt{7}-5\sqrt{14}$
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