Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 9 - Solving Quadratic Equations - 9.1 - Properties of Radicals - Exercises - Page 487: 74

Answer

$w\approx 26$ in

Work Step by Step

The ratio of the length to the width in Golden rectangle is $\frac{1+\sqrt5}{2}$. So: $$\frac{1+\sqrt5}{2}=\frac{42}{w}$$ $$w(1+\sqrt5)=84$$ $$w=\frac{84}{1+\sqrt5}$$ $$w=\frac{84(1-\sqrt5)}{(1+\sqrt5)(1-\sqrt5)}=\frac{84(1-\sqrt5)}{1-5}\approx26$$
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