Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 9 - Solving Quadratic Equations - 9.1 - Properties of Radicals - Exercises - Page 487: 91

Answer

$C\approx4\pi\sqrt {82}\approx113.79$.

Work Step by Step

$C\approx 2\pi \sqrt {\frac{a^{2}+b^{2}}{2}}=2\pi\sqrt {\frac{20^{2}+16^{2}}{2}}$ $=2\pi\sqrt {\frac{400+256}{2}}=2\pi\sqrt {328}$ $=2\pi \sqrt {4\cdot82}=2\pi\sqrt {4}\cdot \sqrt {82}$ $=2\pi (2)\sqrt {82}=4\pi\sqrt {82}$ $C\approx4\pi\sqrt {82}\approx113.79$.
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