Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 9 - Solving Quadratic Equations - 9.1 - Properties of Radicals - Exercises - Page 487: 66

Answer

$g(60)=6\sqrt{5}$ $g(60)\approx 13.42$

Work Step by Step

The given function is $\Rightarrow g(x)=\sqrt{3x}$ Substitute $60$ for $x$. $\Rightarrow g(60)=\sqrt{3(60)}$ Simplify. $\Rightarrow g(60)=\sqrt{180}$ Factor as square term. $\Rightarrow g(60)=\sqrt{36\cdot 5}$ $\Rightarrow g(60)=\sqrt{6^2\cdot 5}$ Use product property of square roots. $\Rightarrow g(60)=\sqrt{6^2}\cdot \sqrt{5}$ Simplify. $\Rightarrow g(60)=6\sqrt{5}$ Rounded to the nearest hundredth. $\Rightarrow g(60)\approx 13.42$
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