Answer
$\sqrt[3]{3}$
Work Step by Step
The given expression is
$=\sqrt[3]{-81}+4\sqrt[3]{3}$
Factor as cube terms.
$=\sqrt[3]{-27\cdot 3}+4\sqrt[3]{3}$
Use product property of square roots.
$=\sqrt[3]{-27}\cdot \sqrt[3]{3}+4\sqrt[3]{3}$
Use $\sqrt [3]{-27}=-3$.
$=-3\sqrt[3]{3}+4\sqrt[3]{3}$
Use distributive property.
$=(-3+4)\sqrt[3]{3}$
Subtract.
$=\sqrt[3]{3}$
