Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 9 - Solving Quadratic Equations - 9.1 - Properties of Radicals - Exercises - Page 487: 75

Answer

$\sqrt{3}+4\sqrt{2}$

Work Step by Step

The given expression is $=\sqrt{3}-2\sqrt{2}+6\sqrt{2}$ Use distributive property. $=\sqrt{3}+(-2+6)\sqrt{2}$ Subtract. $=\sqrt{3}+4\sqrt{2}$
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