Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 9 - Solving Quadratic Equations - 9.1 - Properties of Radicals - Exercises - Page 487: 70

Answer

$=-7\sqrt{2}$ $\approx -9.90$

Work Step by Step

The given function is $=-\sqrt{4c-6ab}$ Substitute $-2$ for $a,8$ for $b,$ and $\frac{1}{2}$ for $c$. $=-\sqrt{4(\frac{1}{2})-6(-2)(8)}$ Simplify. $=-\sqrt{2+96}$ $=-\sqrt{98}$ Factor as square term. $=-\sqrt{49\cdot 2}$ $=-\sqrt{7^2\cdot 2}$ Use product property of square roots. $=-\sqrt{7^2}\cdot \sqrt{2}$ Simplify. $=-7\sqrt{2}$ Rounded to the nearest hundredth. $\approx -9.90$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.