Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 9 - Solving Quadratic Equations - 9.1 - Properties of Radicals - Exercises - Page 487: 78

Answer

$37\sqrt{2}$

Work Step by Step

The given expression is $=9\sqrt{32}+\sqrt{2}$ Factor as square terms. $=9\sqrt{16\cdot 2}+\sqrt{2}$ Use product property of square roots. $=9\sqrt{16}\cdot \sqrt{2}+\sqrt{2}$ Use $\sqrt {16}=4$. $=9\cdot 4\sqrt{2}+\sqrt{2}$ Simplify. $=36\sqrt{2}+\sqrt{2}$ Use distributive property. $=(36+1)\sqrt{2}$ Subtract. $=37\sqrt{2}$
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