Answer
$h(10)=5 \sqrt{2}$
$h(10)\approx 7.07$
Work Step by Step
The given function is
$\Rightarrow h(x)=\sqrt{5x}$
Substitute $10$ for $x$.
$\Rightarrow h(10)=\sqrt{5(10)}$
Simplify.
$\Rightarrow h(10)=\sqrt{50}$
Factor as square term.
$\Rightarrow h(10)=\sqrt{25\cdot 2}$
$\Rightarrow h(10)=\sqrt{5^2\cdot 2}$
Use product property of square roots.
$\Rightarrow h(10)=\sqrt{5^2}\cdot \sqrt{2}$
Simplify.
$\Rightarrow h(10)=5 \sqrt{2}$
Rounded to the nearest hundredth.
$\Rightarrow h(10)\approx 7.07$
