Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 9 - Solving Quadratic Equations - 9.1 - Properties of Radicals - Exercises - Page 487: 72

Answer

$=2\sqrt{17}$ $\approx 8.25$

Work Step by Step

The given function is $=\sqrt{b^2-4ac}$ Substitute $-2$ for $a,8$ for $b,$ and $\frac{1}{2}$ for $c$. $=\sqrt{(8)^2-4(-2)(\frac{1}{2})}$ Simplify. $=\sqrt{64+4}$ $=\sqrt{68}$ Factor as square term. $=\sqrt{4\cdot 17}$ $=\sqrt{2^2\cdot 17}$ Use product property of square roots. $=\sqrt{2^2}\cdot \sqrt{17}$ Simplify. $=2\sqrt{17}$ Rounded to the nearest hundredth. $\approx 8.25$
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