Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 9 - Solving Quadratic Equations - 9.1 - Properties of Radicals - Exercises - Page 487: 68

Answer

$p(8)=\frac{\sqrt{70}}{20}$ $p(8)\approx 0.42$

Work Step by Step

The given function is $\Rightarrow p(x)=\sqrt{\frac{x-1}{5x}}$ Substitute $8$ for $x$. $\Rightarrow p(8)=\sqrt{\frac{8-1}{5(8)}}$ Simplify. $\Rightarrow p(8)=\sqrt{\frac{7}{40}}$ Multiply by $\frac{10}{10}$. $\Rightarrow p(8)=\sqrt{\frac{7}{40}}\cdot \sqrt{\frac{10}{10}}$ Use product property of square roots. $\Rightarrow p(8)=\sqrt{\frac{7\cdot 10}{40\cdot 10}}$ Simplify. $\Rightarrow p(8)=\sqrt{\frac{70}{400}}$ Use quotient property of square roots. $\Rightarrow p(8)=\frac{\sqrt{70}}{\sqrt{400}}$ Simplify. $\Rightarrow p(8)=\frac{\sqrt{70}}{20}$ Rounded to the nearest hundredth. $\Rightarrow p(8)\approx 0.42$
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