Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 9 - Solving Quadratic Equations - 9.1 - Properties of Radicals - Exercises - Page 487: 69

Answer

$=2\sqrt{2}$ $\approx 2.83$

Work Step by Step

The given function is $=\sqrt{a^2+bc}$ Substitute $-2$ for $a,8$ for $b,$ and $\frac{1}{2}$ for $c$. $=\sqrt{(-2)^2+(8)(\frac{1}{2})}$ Simplify. $=\sqrt{4+4}$ $=\sqrt{8}$ Factor as square term. $=\sqrt{4\cdot 2}$ Use product property of square roots. $=\sqrt{4}\cdot \sqrt{2}$ Simplify. $=2\sqrt{2}$ Rounded to the nearest hundredth. $\approx 2.83$
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