Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 9 - Solving Quadratic Equations - 9.1 - Properties of Radicals - Exercises - Page 487: 87

Answer

$18$

Work Step by Step

The given expression is $=(4\sqrt{2}-\sqrt{98})^2$ Factor as square terms. $=(4\sqrt{2}-\sqrt{49\cdot 2})^2$ Use product property of square roots. $=(4\sqrt{2}-\sqrt{49}\cdot \sqrt{2})^2$ Simplify. $=(4\sqrt{2}-7\sqrt{2})^2$ Factor out $\sqrt{2}$. $=[\sqrt{2}(4-7)]^2$ Simplify. $=[\sqrt{2}(-3)]^2$ $=(-3\sqrt{2})^2$ $=18$
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