Answer
$y=C_{1}e^t+C_{2}te^t+C_{3}t^2e^{t}$
Work Step by Step
let : $\;\;\;\;y=e^{rt}$
${y}'=re^{rt}\;\;\;\;\;\;\;\;\;{y}''=r^2e^{rt}\;\;\;\;\;\;\;\;{y}'''=r^3e^{rt}\\\\$
$(r^3-3r^2+3r-1)e^{rt}=0\\\\$
$\Rightarrow r^3-3r^2+3r-1=0\\\\$
$(r-1)(r^2-1)=0\;\;\;\;\;\;\rightarrow \;\;\;\;\;\;(r-1)^3=0\\\\$
$r=1$
$y=C_{1}e^t+C_{2}te^t+C_{3}t^2e^{t}$