Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 7: Transcendental Functions - Section 7.7 - Hyperbolic Functions - Exercises 7.7 - Page 430: 48

Answer

$\coth (5-x) +C$

Work Step by Step

As we are given that $\int csch^2(5-x) dx$ The given integral can be re-written as follows:$\int csch^2(5-x) dx=\int csch^2(x-5) dx$ Consider $x-5=t \implies dx =dt$ This implies, $\int csch^2(5-x) dx=\int csch^2 t dt=-\coth t +C= -\coth (x-5) +C=\coth (5-x) +C$$
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