Answer
$\cosh (2x+1)$
Work Step by Step
Given: $y=\dfrac{1}{2} \sinh (2x+1)$
Since, we know that $\dfrac{d}{dx} (\cosh x)=\sinh x$
Then, we get $\dfrac{dy}{dx}= (2)\dfrac{1}{2} \cosh (2x+1) $
or, $= \cosh (2x+1)$
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 7: Transcendental Functions - Section 7.7 - Hyperbolic Functions - Exercises 7.7 - Page 430: 14
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