Answer
$5 \cosh(\dfrac{ x}{5})+C$
Work Step by Step
As we are given that $\int \sinh (\dfrac{x}{5}) dx$
Since, $\int \sinh x dx=\cosh x +C$
Therefore, $\int \sinh (\dfrac{x}{5}) dx=\dfrac{ \cosh(\dfrac{ x}{5})}{\dfrac{1}{5}}+C$
or, $= 5 \cosh(\dfrac{ x}{5})+C$
