Answer
$\dfrac{\cosh (2x)}{2}+C$
Work Step by Step
As we are given that $\int \sinh (2x) dx$
Since,: $\int \sinh x dx=\cosh x +C$
Hence, $\int \sinh (2x) dx=\dfrac{\cosh (2x)}{2}+C$
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 7: Transcendental Functions - Section 7.7 - Hyperbolic Functions - Exercises 7.7 - Page 430: 41
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