Answer
$\frac {(lnx)^3} 3+C$
Work Step by Step
$u=lnx, du= \frac 1 x dx$
$\int \frac {(lnx)^2} x dx$
$\int (lnx)^2(\frac 1 x)dx$
$\frac {(lnx)^3} 3+C$
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