Answer
$\int \frac{du}{u}$
$u= t^{2}+t-4$
Work Step by Step
Try it:
$du=(2t+1)dt$
$\int \frac{du}{u}=\ln |u| +C$
$\ln |t^{2}+t-4| +C$
$\int \frac{du}{u}$
$u= t^{2}+t-4$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 8 - Integration Techniques, L'Hopital's Rule, and Improper Integrals - 8.1 Exercises - Page 512: 6
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