Answer
$\int u^{n}du$
$u=5x-3, n=4$
Work Step by Step
Try it:
$du=5dx$
$\frac{1}{5} \int (5x-3)^{4}(5)dx$
$\frac{1}{5} \int u^{4}(5)du$
$\frac{1}{5}$($\frac{u^{5}}{5}+C)$
$\frac{1}{5}$($\frac{(5x-3)^{5}}{5}+C)$
($\frac{(5x-3)^{5}}{25}+C)$
$\int u^{n}du$
$u=5x-3, n=4$