Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 8 - Integration Techniques, L'Hopital's Rule, and Improper Integrals - 8.1 Exercises - Page 512: 27

Answer

$\frac x {15} (48x^5+200x^3+375)+C$

Work Step by Step

$\int (5+4x^2)^5$ $\int (25+40x^2+16x^4)dx$ $25x+\frac {40}3 x^3+\frac {16}5 x^5+C$ $\frac x {15} (48x^5+200x^3+375)+C$
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