Answer
$- \frac{5}{2(t+6)^2}+C$
Work Step by Step
$\int \frac 5{(t+6)^3}dt$
$\int \frac 5{u^3}dt$
$5\int u^{-3}dt$
$5(\frac {u^{-2}}{-2})+C$
$-\frac 5{2u^2}+C$
$- \frac{5}{2(t+6)^2}+C$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 8 - Integration Techniques, L'Hopital's Rule, and Improper Integrals - 8.1 Exercises - Page 512: 16
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