Answer
$\frac 1 4 arctan (\frac {2x+1} 8)+C$
Work Step by Step
$\int \frac 4 {4x^2+4x+65}dx$
$\int \frac 1 {(x+\frac 1 2)^2+16}dx$
$\frac 1 4 arctan (\frac {x+\frac 1 2} 4)+C$
$\frac 1 4 arctan (\frac {2x+1} 8)+C$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 8 - Integration Techniques, L'Hopital's Rule, and Improper Integrals - 8.1 Exercises - Page 512: 45
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