Answer
$3(x+4)-12ln|x+4|+C$
Work Step by Step
$\int \frac {3x}{x+4}dx$
$u=x+4; du=dx; x=u-4$
$\int \frac {3(u-4)} u du$
$3\int 1du-12\int \frac1 u du$
$3u-12ln|u|+C$
$3(x+4)-12ln|x+4|+C$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 8 - Integration Techniques, L'Hopital's Rule, and Improper Integrals - 8.1 Exercises - Page 512: 24
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