Answer
$-\frac1 4 arcsin(4t-1)+C$
Work Step by Step
$\int \frac {-1}{\sqrt {1-(4t+1)^2}}dt$
$u=4t+1; du=4dt$
$-\frac1 4 \int \frac4 {\sqrt {1-(4t+1)^2}}dt$
$-\frac1 4 arcsin(4t-1)+C$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 8 - Integration Techniques, L'Hopital's Rule, and Improper Integrals - 8.1 Exercises - Page 512: 39
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