Answer
$-\frac 1 2 (ln(cosx))^2+C$
Work Step by Step
$u=ln(cosx); du=-tanxdx$
$-\int ln(cosx)(-tanx)dx$
$-\int udu$
$-\frac1 2 u^2+C$
$-\frac 1 2 (ln(cosx))^2+C$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 8 - Integration Techniques, L'Hopital's Rule, and Improper Integrals - 8.1 Exercises - Page 512: 36
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