Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 8 - Integration Techniques, L'Hopital's Rule, and Improper Integrals - 8.1 Exercises - Page 512: 41

Answer

$\frac 1 2 ln|cos(\frac 2 t)|+C$

Work Step by Step

$Let u=cos(\frac 2 t), du=\frac {2sin(\frac 2 t)}{t^2}dt$ $\int \frac{tan\frac2 t}{t^2}dt$ $\frac1 2 \int \frac 1{cos(\frac 2 t)}[\frac {2sin(\frac 2 t)}{t^2}]dt$ $\frac 1 2 ln|cos(\frac 2 t)|+C$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.