Chapter 8 - Integration Techniques, L'Hopital's Rule, and Improper Integrals - 8.1 Exercises - Page 512: 26

$\frac 1 2 ln|2x+5|-\frac 1 2 ln|2x-5|+C$

$\int (\frac 1 {2x+5}- \frac 1 {2x-5})dx$ $\int \frac 1 {2x+5}$- $\int \frac 1 {2x-5}dx$ $u=2x+5; \frac 1 2 du=dx$ $u=2x-5;\frac 1 2 du=dx$ $\frac 1 2 \int \frac 1 u du-\frac 1 2 \int \frac 1 u du$ $\frac 1 2 ln|2x+5|-\frac 1 2 ln|2x-5|+C$