Answer
$-e^{1/t}+C$
Work Step by Step
$\int e^{t^{-1}}t^{-2}dt$
$Let u = t^{-1}, du = -t^{-2}dt$
$-\int e^{t^{-1}}(-t^{-2})dt$
$-\int e^udu$
$-e^u+C$
$-e^{t^{-1}} +C$
$-e^{1/t}+C$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 8 - Integration Techniques, L'Hopital's Rule, and Improper Integrals - 8.1 Exercises - Page 512: 42
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