Answer
$2x^2+\frac 1 {2x+3}+C$
Work Step by Step
$\int 4x -\frac 2 {(2x+3)^2}dx$
$4\int xdx -2\int \frac 1 {(2x+3)^2}dx$
$2x^2-\frac {(2x+3)^-1}{-1}+C$
$2x^2+\frac 1 {2x+3}+C$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 8 - Integration Techniques, L'Hopital's Rule, and Improper Integrals - 8.1 Exercises - Page 512: 20
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